Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
इसी | 111 | 8 | 1 | 8.0000 |
लिए | 1097 | 51 | 7 | 7.2857 |
आम | 70 | 7 | 1 | 7.0000 |
साबित | 52 | 7 | 1 | 7.0000 |
चला | 37 | 6 | 1 | 6.0000 |
मीडिया | 59 | 6 | 1 | 6.0000 |
न | 133 | 12 | 2 | 6.0000 |
होते | 56 | 6 | 1 | 6.0000 |
खिलाफ | 235 | 16 | 3 | 5.3333 |
दस | 40 | 5 | 1 | 5.0000 |
जुलाई | 37 | 5 | 1 | 5.0000 |
हिंसा | 32 | 5 | 1 | 5.0000 |
बैंकों | 36 | 5 | 1 | 5.0000 |
अगले | 50 | 5 | 1 | 5.0000 |
प्रक्रिया | 38 | 5 | 1 | 5.0000 |
बनाए | 41 | 5 | 1 | 5.0000 |
15 | 54 | 5 | 1 | 5.0000 |
30 | 57 | 5 | 1 | 5.0000 |
चाहता | 32 | 5 | 1 | 5.0000 |
आईपीएल | 28 | 5 | 1 | 5.0000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
तौर | 80 | 1 | 7 | 0.1429 |
उसे | 132 | 1 | 6 | 0.1667 |
सचिव | 45 | 1 | 6 | 0.1667 |
जबकि | 141 | 1 | 6 | 0.1667 |
रहे | 528 | 5 | 25 | 0.2000 |
राय | 53 | 1 | 5 | 0.2000 |
बजे | 93 | 3 | 13 | 0.2308 |
करने | 661 | 14 | 56 | 0.2500 |
उससे | 43 | 1 | 4 | 0.2500 |
बारे | 187 | 1 | 4 | 0.2500 |
बल्कि | 61 | 1 | 4 | 0.2500 |
जनरल | 19 | 1 | 4 | 0.2500 |
मुकाबले | 42 | 1 | 4 | 0.2500 |
मामला | 71 | 1 | 4 | 0.2500 |
तरफ | 46 | 1 | 4 | 0.2500 |
संबंध | 59 | 1 | 4 | 0.2500 |
अध्ययन | 26 | 1 | 4 | 0.2500 |
मौके | 53 | 1 | 4 | 0.2500 |
आरोपी | 44 | 1 | 4 | 0.2500 |
उसका | 46 | 1 | 4 | 0.2500 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II